Okay. I have logged out of the Academy for today, but I will attempt the exercise tomorrow. Hope you don’t mind. Thank you!
Minimum
function min(a,b) {
if (a < b) {
return a;
} else {
return b;
}
}
Recursion
function isEven(num) {
if (num % 2 === 0) {
return true;
} else if (num % 2 === 1) {
return false;
} else {
return isEven(-num);
}
}
Bean Counting
function countChar(string,ch) {
let counted = 0;
for (let count = 0; count < string.length; count ++) {
if (string[count] === ch) {
counted += 1;
}
} return counted;
}
function countBs(string) {
return countChar(string, "B");
}
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Here is my tentative answer to #3, the Bean Counting exercise. I had to refer to other students’ posts to get an idea of how the problem needed to be set up.
function countChar(str, ch) {
var count = 0;
for (var i = 0; i < str.length; i++) {
if (str[i] == ch) {
count++;
}
}
return count;
}
function countBs(str) {
return countChar(str, "B");
}
console.log(countBs("Total number of beans"))
The result in my console came out 0. What did I do incorrectly?
Thank you!
I dont see were are the exercises 
@jgentry, The function only counts capital letter B’s. As thats what you have provided. Provide small letter “b” so that your function will count it.
Hi @Lacho, Please scroll on top of the page to find the questions link that Ivan has provided. You will find the question prompts there.
Thanks.
1 Like
That’s not a T, it’s an I.
I barely understood what you were saying. Please discuss more clearly.
Thank you.
1 Like
There was a typo. Please check my response again. I have edited the text.
1 Like
Okay. I think I can handle it now. I’ll give it another go.
Thanks!
1 Like
I got 2 in my console. Did I do something incorrectly, or is that the result expected?
1 Like
//exercise minimum
function min(a, b) {
if (a < b) return a;
else return b;
}
1 Like
function isEven(N) {
if (N == 0) return true;
else if (N == 1) return false;
else if (N < 0) return isEven(-N);
else return isEven(N - 2);
}
console.log(isEven(50));
console.log(isEven(75));
console.log(isEven(-1));
1 Like
Minimum Exercise
var min = function(k,d){
return (k < d ? k : d);
}
Recursion Exercise
function even(number)
{ if (number == 0) return true;
else if (number == 1) return false;
else if (number < 0) return even(-n);
else return even(number - 2);}
Bean Counting Exercise
var count = function(str,char){
var beans = 0;
if (typeof(str) !== "string" ) return 0;
for(var number=0;number<str.length;number++){
if(str[number]===char[0]) beans++;
}
return beans;
};
var countBeans = function(str){
return count(str,"B");
};
1 Like
Chapter 3 Exercises:
Minimum
<script>
function min(param1, param2){
//if param2 is undefined (he refers to this as "edge case")
if (param2 === undefined){
//return param1
return param1;
}
//if param1 is less than param2
if (param1 < param2) {
return param1;
}
else {
return param2;
}
}
console.log(min(0,10));
//0
console.log(min(0, -10));
// -10
console.log(min(4));
//4
console.log(min(5,5));
//5
</script>
Recursion
<script>
function isEven(n) {
//to deal with the minus 1 (edge case)
if (n < 0) {
n = Math.abs(n); //absolute value
}
//base case follows, if n is zero, return true
if (n === 0) {
return true;
}
//if n is one, return false
if (n ===1) {
return false;
} //base case ends
//in all other cases, apply isEven to n minus two - recursive case
return isEven (n - 2);
}
console.log(isEven(50));
//true
console.log(isEven(75));
//false
console.log(isEven(-1));
//false
console.log(isEven(-14));
//true
</script>
Bean Counting (1)
<script>
//part 1 of 2
function countBs(string) {
//create a result, set it to zero
let result = 0;
//loop over the string
for(let i=0; i<string.length; i++) {
//if current character is a "B"
if (string[i] === 'B') {
//we want to increment our result by one
result +=1; //result++ OR result = result + 1 (all the same)
}
}
//return result
return result;
}
function countChar(string, character) { //this is to get the "k" below
//create a result, set to zero
let result = 0;
//loop over the string
for(let i=0; i<string.length; i++) {
//if current character matches input character
if (string[i] === character) { //he removed the single quotes
//we want to increment our result by one
result +=1; //result++ OR result = result + 1 (all the same)
}
}
//return result
return result;
}
console.log(countBs("BBBBBC"));
// 5
console.log(countChar("kakkerlakkk", "k"));
// 6
</script>
Bean Counting (2)
<script>
//part 2 of 2 - answer to second part of question
function countBs(string) {
//return a call to countChar with input and "B"
return countChar(string, 'B');
}
function countChar(string, character) { //this is to get the "k" below
//create a result, set to zero
let result = 0;
//loop over the string
for(let i=0; i<string.length; i++) {
//if current character matches input character
if (string[i] === character) { //he removed the single quotes
//we want to increment our result by one
result +=1; //result++ OR result = result + 1 (all the same)
}
}
//return result
return result;
}
console.log(countBs("BBBBC"));
// 4
console.log(countChar("kakkerlakkk", "a"));
// 2
</script>
I did have help from internet, YouTube, previous answers from students…this is pretty humbling.
1 Like
Minimum
function min(a,b) {
if (a < b) return a;
else return b;
}
console.log(min(0, 10));
// → 0
console.log(min(0, -10));
// → -10
Recursion
function isEven(n) {
if (n == 0) return true;
else if (n == 1) return false;
else if (n < 0) return isEven(-n);
else return isEven(n - 2);
}
console.log(isEven(50));
// → true
console.log(isEven(75));
// → false
console.log(isEven(-1));
// → false
Bean Counting
function countChar(string, ch) {
let counted = 0;
for (let i = 0; i < string.length; i++) {
if (string[i] == ch) {
counted += 1;
}
}
return counted;
}
function countBs(string) {
return countChar(string, “B”);
}
console.log(countBs(“BBC”));
// → 2
console.log(countChar(“kakkerlak”, “k”));
// → 4
1 Like
3.1 Minimum
function min(x,y) {
if (x < y) return x;
else return y;
}
3.2 Recursion
Same result, but without recursion
function isEven(num){
if(num%2==0) return true;
else if (num == -1) return "??";
else return false;
}
3.3 Bean counting
function countBs( str){
return countChar(str, "B");
}
function countChar(str, value){
let count = 0;
for(let x = 0; x < str.length; x++){
if(str[x] === value) count += 1;
}
return count;
}
2 Likes
Minimum:
function min(a,b){
if(a<b){
document.write(a)
}
else{
document.write(b)
}
}
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function isEven(N){
if (N==0){
document.write(“even”)
}
else if (N==1){
document.write(“odd”)
}
else if(N<0){
return isEven(-N)
}
else{
return isEven(N-2)
}
}
1 Like
Bean counter
function countChar(string,x) {
let count = 0;
for (let N=0; N<string.length; N++){
if (string[N]==x) {
count++;
}
}
document.write(count)
}
1 Like
1. Minimum:
function min(a,b){
if(a>b){
return(b);
}else{
return(a);
}
}
var answer = min(12,14);
document.write(answer + "<br>")
- isEven
function isEven(a){
if(a == 0){
return ("True")
}else if(a == 1){
return ("False")
}else if (a < 0){
return(isEven(-a))
}
else{
return (isEven(a -2))
}
}
document.write(isEven(-1))
</html>
function countBs(string){
let count = 0
for (let i = 0; i < string.length; i++){
if(string[i] == "B"){
count++
}
} return (count);
}
document.write(countBs("TheQuickBrownFoxWasVeryBBBad"))
// 4
PART 2:
function countChar(string, char){
let count = 0
for (let i = 0; i < string.length; i++){
if(string[i] == char){
count++
}
} return (count);
}
document.write(countChar("TheQuickBrownFoxWasVeryBBBad", "e"))
// return 2
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//Minimum Function
function mn(n1,n2){if(n1<n2) return n1; else return n2;}
console.log (mn(-50,3))
//Recursion
function is_even_or_odd(n) {
if (n == 0) return true;
else if (n == 1) return false;
else if (n < 0) return is_even_or_odd(-n);
else return is_even_or_odd(n - 2);
}
console.log(is_even_or_odd(20))
console.log(is_even_or_odd(85))
console.log(is_even_or_odd(-93))
console.log(is_even_or_odd(-30))
//Bean Counting
function charcount(string, ch) {
let tc = 0;
for (let i = 0; i < string.length; i++) {
if (string[i] == ch) {
tc += 1;
}
}
return tc;
}
function countBs(string) {
return charcount(string, “B”);
}
console.log(countBs(“Big Burger with Butter”));
console.log(charcount(“karaoke kills singing skills”, “k”));
1 Like