for (var i=1; i <= 100; i++){
if (i % 3 == 0) document.write("Fizz
“);
else if (i % 5 == 0) document.write(” Buzz
");
else if (i % 3 && i % 5 == 0) document.write("FizzBuzz
");
else document.write(i + “
”);
}
Triangle Loop
for (let sign = “#”; sign.length < 8; sign =+ “#”) {
console.log(sign);}
I did the exercises a bit to soon. At first i didn’t realize length could be used this way. So i used sign < “########”. Which worked but looks less professional.
FizzBuzz Loop
for (let number = 1; number <= 100; number++) {
if (number % 15 == 0) {
console.log(“fizzbuzz”);
} else if (number % 5 == 0) {
console.log(“buzz”);
} else if (number % 3 == 0) {
console.log(“fizz”);
} else {
console.log(number);
}
}
Again, i did this one too early and was quite pleased with myself to see it work. However scrolling down this page while posting this answer i saw the user Bitworld post a more professional tweak. Instead of:
if (number % 15 == 0)
He used:
else if (i % 3 && i % 5 == 0)
Chessboard Loop
let total = “”;
let size = “8”;for (a = 0; a < size; a++) {
for (b = 0; b < size; b++) {
if ((a + b) % 2 == 0) {total += " ";}
else {total += “#”;}
}
total += “\n”;
}
console.log(total);
I needed help for this one, couldn’t figure out the logic behind it at first. But finally!
for(var count=1; count<100; count++){
if (count%3==0)
document.write("<h2>Fizz</h2>")
else if (count%5==0)
document.write("<h2>Buzz</h2>")
else
document.write("<h2>" + count + "</h2>")
}
for(var count=1; count<9; count++){
if (count%2==0)
console.log(" # # # #")
else
console.log("# # # # ")
}
FizzBuzz
for(i=1; i<=100; i++){
!(i%5)?
!(i%3)?
console.log('FizzBuzz'):console.log('Buzz')
:!(i%3)?console.log('Fizz'):console.log(i);
}
/* checks for divisibility by 5, then by three in the both cases of true and false */
ChessBoard
size = 8;
output='';
for(i=0; i<size; i++){
for(j=0; j<size; j+=2){
!(i%2)?output+=' #':output+='# ';
}
output+='\n';
}
console.log(output);
/*
this solution may be looked at in a binary manner, where the outputs are
either # and a space, or a space and #
of course, checking each position for a space or a # is possible, though this
method requires less iterations, since we increment by two to iterate each line
for half of the checkerboard size
*/
FizzBuzz
let counter = 100;
for(let number = 0; number <= counter; number ++){
if(number%3==0 && number%5!==0){
console.log("Fizz");
}
else if(number%5==0 && number%3!==0){
console.log("Buzz");
}else if(number%3==0 && number%5==0){
console.log("FizzBuzz");
}else{
console.log(number);
}
}
Checks if the number is divisible by 3, then by 5, then by both. If neither, console.logs the number.
ChessBoard
let size = 8;
let total = "";
for(let row = 0; row < size; row++){
for(let column = 0; column < size; column++){
if((row+column)%2 == 0){
total+=" ";
}else{
total+="#";
}
}
total+="\n";
}
console.log(total);
Defines the number of rows; then in each row, it defines which character each column will have; then adds to the row a new line, and continues doing this for the number of rows defined
Wow, short and easy to read.
My chessboard needs more code:
let toPrint = "";
let flipflop = true;
for(let line = 1; line<=grid; line++)
{
if(line%2){flipflop=true;}
else{flipflop=false;}
for(let collumn = 1; collumn <= grid; collumn++)
{
if(flipflop){
toPrint=toPrint+" ";
flipflop=false;
}
else{
toPrint=toPrint+"#";
flipflop = true
}
}
toPrint = toPrint+"\n";
}
console.log(toPrint);
What is the trick to get the code that simple?
hell of a ride for me…
Triangle:
for (let i= “#”; i.length<=7; i+="#")
document.write(i + “
”);
fizzbuzz:
for (let i=1; i<=100; i++) {
if (i%3==0) {document.write(“fizz”);}
else if (i%5==0) {document.write(“buzz”);}
else {document.write(i)};
}
chessboard:
let size = 10;
let board = “”;
for (var y= 0; y <size; y++){
for (let x=1; x<=size; x++){
if ((x+y)%2==0){
board += " ";
} else { board += “#”;
}
} board += “\n”;}
console.log(board);
Lopping a triangle:
for(let i="#"; i.length<8; i+="#"){
console.log(i);
}
FizzBuzz
let n = 1;
while(n < 101){
if(n % 3 == 0 && n % 5 !== 0){
console.log("Fizz");
}
else if (n % 3 !== 0 && n % 5 == 0) {
console.log("Buzz");
}
else if (n % 3 == 0 && n % 5 == 0) {
console.log("FizzBuzz");
}
else {
console.log(n);
}
n++;
}
Chessboard:
let size = 10;
let line = "# ";
let line_odd = " #";
let i = 0;
for(let i=0; i < size; i++){
if (i % 2 == 0){
while(line_odd.length<size){
line_odd+=" #"
}
console.log(line_odd);
}
else {
while(line.length<size){
line+="# "
}
console.log(line);
}
}
Seems I solved this differently than most. I didn’t use console.log…
I contemplated using continue but decided to reorder the conditionals. You wouldn’t believe what held me up the longest… I had “and” instead of &&. That’s what I get for decades of writing Pascal.
FizzBuzz
for (i=1;i<=100;i++)
{
if ((i % 3)==0)
{
if ((i % 5)==0) {console.log(“fizzbuzz”);}
else {console.log(“fizz”);}
}
else if ((i % 5)==0){console.log(“buzz”);}
else {console.log(i);}
}
//I can’t believe this one really weeds out a significant number of programmers.
Chess Board
let gridSize = 8;
let myline = “”;
for (i = 1; i <= gridSize; i++)
{
if ((i % 2)==1){
for (j=1; j<= gridSize; j++){
if ((j % 2) == 1) {
myline += " "}
else {myline += “#”}}
console.log(myline);}
else{
for (j=1; j<= gridSize; j++){
if ((j % 2) == 1) {
myline += “#”}
else {myline += " "}}
console.log(myline);}
myline = “”;
}
// you can set gridSize to any number you want. I don’t want to figure out how to tie a prompt in there right now.
var num_rows = 7;
for(row = 0; row < num_rows; row++){
var toPrint = "#";
for(var column = 0; column<row; column++){
toPrint += "#";
}
console.log(toPrint);
}
for (i=1; i<=100; i++){
if (i%3==0){
if(i%5==0){
//If it is both print FizzBuzz
console.log ("FizzBuzz");
}
else {
//If it is divisible by 3 than do this code
console.log ("Fizz");
}
}
else if (i%5==0){
//If it is divisible by 5 and not 3 do this code
console.log ("Buzz");
}
else (console.log (i));
}
The above code displayed the following:
1 2 Fizz 4 Buzz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz 16 17 Fizz etc……
substituting “Fizz” if number divisible by 3
substituting “Buzz” if number divisible by 5
substituting “FizzBuzz” if number divisible by both 3 and 5
ChessBoard
ChessBoard
I know these aren’t the correct solutions, but they are what I got my first time around solving them. For instance, I am aware that I didn’t even use a /n on the chess board exercise and it’s not scalable yet. I’m excited I got my results to look how they should, nonetheless.
-
Looping A Triangle
var num_rows = 7; for(var row = 0 ; row < num_rows; row++){ var toPrint = "#"; for(var column = 0; column<row; column++){ toPrint += "#"; } console.log(toPrint); }
-
FizzBuzz
var printFizz = "Fizz"; var printBuzz = "Buzz"; var printFizzBuzz = "Fizz Buzz"; for(n = 0; n <= 100; n++){ if(n % 3 == 0) console.log(printFizz); if(n % 5 == 0) console.log(printBuzz); else { console.log(n) if(printFizz && printBuzz) console.log(printFizzBuzz); }
-
Chessboard
for (let row = 1; row <= 8; row++) { if (row % 2 == 0) console.log ("#" + " " + "#" + " " + "#" + " " + "#" + " "); else (console.log (" " + "#" + " " + "#" + " " + "#" + " " + "#")) }
FIZZBUZZ
document.write("<br><br>"+ "TEST 2: fizzbuzz" + "<br><br>")
for (i=1; i <= 100; i++)
{
if ((i%3) == 0 && (i%5) == 0){
document.write('FizzBuzz'+'<br>');
}
else {
if ((i%3) == 0)
{
document.write('fizz'+'<br>');
}
else {
if ((i%5) == 0)
{
document.write('buzz'+'<br>');
}
else {
document.write(i);
}
}
}
}
CHESSBOARD
document.write("<br><br>"+ "TEST 3: chessboard v2" + "<br><br>")
var height = 8;
var width = 16;
//print chessboard
for (i=1; i <= height; i++)
{
for (j=1; j <= width; j++)
{
if ( (i%2) == 0)
{
if ((j%2) == 0)
{document.write(' ');}
else
{document.write('#');}
}
else {
if ((j%2) == 0)
{document.write('#');}
else
{document.write(' ');}
}
}
document.write('<br>');
}
-
Looping and triangle
let stringToPrint = "#"; for (let index = 0; index < 7; index++) { console.log(stringToPrint); stringToPrint += "#"; }
-
FizzBuzz
for (let i = 1; i < 101; i++) { if (i % 3 == 0 && i % 5 == 0) { console.log("FizzBuzz"); } else if (i % 3 == 0) { console.log("Fizz"); }else if (i % 5 == 0) { console.log("Buzz"); }else { console.log(i); } }
-
Chessboard
let boardSize = 20; let board = ""; for (let i = 0; i < boardSize; i++) { for (let j = 0; j < boardSize; j++) { if (i % 2 == 1) { if (j % 2 == 0) { board += "#"; } else { board += " "; } } else { if (j % 2 == 1) { board += "#"; } else { board += " "; } } } board += "\n"; } console.log(board);
Looping a triangle
for(var row = 0; row < 7; row++){
var toPrint = “#”;
for(var column =0; column<row; column++){
toPrint += “#”;
}
console.log(toPrint);
}
FizzBuzz
for (number=1; number<=100; number++)
if(number % 5 == 0 && number % 3 == 0) {
console.log("FizzBuzz");
continue;
}
else if (number % 5 == 0 && number % 3 !== 0) {
console.log("Buzz");
continue;
}
else if (number % 3 == 0) {
console.log("Fizz");
continue;
}
else {
(number);
console.log(number)
continue;
}
Chessboard
var size = 8;
var board = "";
for (a = 0; a < size; a++) {
for (b = 0; b < size; b++) {
if ((a + b) % 2 == 0) {
board += " ";
} else {
board += "#";
}
}
board += "\n";
}
console.log(board);
here’s what I have so far. The browser keeps crapping out on me, so here I go with it
Triangle
Second Projectvar num_row = 8;
for(var row = 0; row < num_row; row++){
var print_to = “#”;
for(var column = 0; column<row; column++){
print_to += “#”
}
console.log(print_to)
}
Chessboard (this one was a bitch)
Second Projectvar num_row = 8;
for(var row = 0; row < num_row; row++){
var print_to = “#”;
for(var column = 0; column<row; column++){
print_to += “#”
}
console.log(print_to)
}
Fizzbuzz
for(var num = 0; num < 100; num++){
if(num % 3 == 0)
console.log="fizz";
else if(num % 5 ==0)
console.log="buzz";
else if(num % 15 ==0)
console.log="fizzbuzz";
else console.log="num";
}
Any constructive criticism is welcomed. I can use the feedback/help
FizzBuzz
for (let i = 1; i <= 100; i++) {
if ((i % 3 == 0) && (i % 5 == 0)) {
console.log(“FizzBuzz”);
} else if (i % 3 == 0) {
console.log(“Fizz”);
} else if (i % 5 == 0) {
console.log(“Buzz”);
} else {
console.log(i);
}
}
Chessboard
let pair = " # # # #";
let impair = "# # # # ";
for(let i = 0; i < 8; i++) {
if(i % 2 == 0) {
console.log(pair);
} else {
console.log(impair);
}
}
EXERCISES
1.For Loop
for ( triangle = “#”; triangle.length < 8; triangle+="#") {
console.log(triangle);
}
for( i=0; i <= 100; i++) {
if (i % 3 === 0 && i % 5 === 0) {console.log(“FizzBuzz”);}
else if (i % 3 === 0 && i % 5 != 0) { console.log (“Fizz”);}
else if (i % 5 === 0 ) { console.log(“buzz”);}
else {console.log(i);}
}
3.
Need Help!
I admit for the first exercise I was able to find the solution on my own.
The second and third exercise I had to look at the solutions.
I only made to 1, 2, Fizz and my program stopped because I didn’t know how to display “Fizz”.
And I made a grid containing # but it didn’t correctly for an 8 x 8 grid.